Write a Program to Check Leap Year or Not – Technic Dude

Program to Check Leap Year or not in c language , java language and python language by technic dude

Program to Check Leap Year in C

#include <stdio.h>
int main() {
   int year;
   printf("Enter a year: ");
   scanf("%d", &year);

   // leap year if perfectly divisible by 400
   if (year % 400 == 0) {
      printf("%d is a leap year.", year);
   }
   // not a leap year if divisible by 100
   // but not divisible by 400
   else if (year % 100 == 0) {
      printf("%d is not a leap year.", year);
   }
   // leap year if not divisible by 100
   // but divisible by 4
   else if (year % 4 == 0) {
      printf("%d is a leap year.", year);
   }
   // all other years are not leap years
   else {
      printf("%d is not a leap year.", year);
   }

   return 0;
}

Output

Enter a year: 1900
1900 is not a leap year.
Output 2

Enter a year: 2012
2012 is a leap year.

Program to Check Leap Year in JAVA

import java.util.Scanner;
public class LeapYear {
   public static void main(String[] args){
      int year;
      System.out.println("Enter an Year :: ");
      Scanner sc = new Scanner(System.in);
      year = sc.nextInt();

      if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
         System.out.println("Specified year is a leap year");
      else
         System.out.println("Specified year is not a leap year");
   }
}

Output

Enter an Year ::
2020
Specified year is a leap year

Program to Check Leap Year Python

Python program to check if year is a leap year or not

year = 2020

# To get year (integer input) from the user
# year = int(input("Enter a year: "))

if (year % 4) == 0:
   if (year % 100) == 0:
       if (year % 400) == 0:
           print("{0} is a leap year".format(year))
       else:
           print("{0} is not a leap year".format(year))
   else:
       print("{0} is a leap year".format(year))
else:
   print("{0} is not a leap year".format(year))

Output

2020 is a leap year

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