Program to Check Leap Year or not in c language , java language and python language by technic dude

## Program to Check Leap Year in C

``````

#include <stdio.h>
int main() {
int year;
printf("Enter a year: ");
scanf("%d", &year);

// leap year if perfectly divisible by 400
if (year % 400 == 0) {
printf("%d is a leap year.", year);
}
// not a leap year if divisible by 100
// but not divisible by 400
else if (year % 100 == 0) {
printf("%d is not a leap year.", year);
}
// leap year if not divisible by 100
// but divisible by 4
else if (year % 4 == 0) {
printf("%d is a leap year.", year);
}
// all other years are not leap years
else {
printf("%d is not a leap year.", year);
}

return 0;
}

``````

## Output

``````

Enter a year: 1900
1900 is not a leap year.
Output 2

Enter a year: 2012
2012 is a leap year.``````

## Program to Check Leap Year in JAVA

``````import java.util.Scanner;
public class LeapYear {
public static void main(String[] args){
int year;
System.out.println("Enter an Year :: ");
Scanner sc = new Scanner(System.in);
year = sc.nextInt();

if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
System.out.println("Specified year is a leap year");
else
System.out.println("Specified year is not a leap year");
}
}
``````

## Output

``````
Enter an Year ::
2020
Specified year is a leap year``````

## Program to Check Leap Year Python

Python program to check if year is a leap year or not

``````
year = 2020

# To get year (integer input) from the user
# year = int(input("Enter a year: "))

if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
``````

## Output

``````

2020 is a leap year``````